X^2-9x-285=0

Solution for X^2-9x-285=0 equation:

X^2-9X-285=0

a = 1; b = -9; c = -285;
Δ = b2-4ac
Δ = -92-4·1·(-285)
Δ = 1221
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{1221}}{2*1}=\frac{9-\sqrt{1221}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{1221}}{2*1}=\frac{9+\sqrt{1221}}{2}
$